Web17 Aug 2012 · SELECT CONVERT (DATETIME, '2012-08-17', 111) And if that doesn't work for some reason - you could always just strip out the dashes and then you have the totally … Web1 You need to apply a format matching the input string: To_Date (Substr (var1,1,9), 'ddmonyyyy') returns a DATE. If you want to cast it back to a string: To_Char (To_Date (Substr (var1,1,9), 'ddmonyyyy'), 'mm/dd/yyyy') Share Improve this answer Follow answered Nov 22, 2024 at 17:48 dnoeth 59.2k 4 38 55 Add a comment Your Answer
SUBSTR - Oracle Help Center
WebThe SUBSTRING () function extracts some characters from a string. Syntax SUBSTRING ( string, start, length) Parameter Values Technical Details More Examples Example Extract … WebThe SUBSTR functions return a portion of char, beginning at character position, substring_length characters long. SUBSTR calculates lengths using characters as defined … steps tickets birmingham
Oracle SQL To_Char(interval) is not using my format string?
WebThe to_* functions all use a common calling convention: the first argument is the value to be formatted, and the second argument is a template that defines the output or input format. The patterns used by these templates are described in … Web14 Apr 2024 · Substring You can extract part of a string, from a specified offset with a specified length. Note that the offset index is 1-based. Each of the following expressions will return the string ba. Oracle SUBSTR (‘foobar’, 4, 2) Microsoft SUBSTRING (‘foobar’, 4, 2) PostgreSQL SUBSTRING (‘foobar’, 4, 2) MySQL SUBSTRING (‘foobar’, 4, 2) Comments Web2 Jan 2024 · substr (to_char (to_date ('01-02-2024','mm-dd-yyyy'), 'DD-MON-RR'),4,3) Therefore, the substr is working on the string 02-JAN-18, and the 3 characters starting from the 4th character is JAN. Rather than use substr on a date, you would do better to use … steps ti renew norton antivirus